x^2-5x=2x^2-5x

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Solution for x^2-5x=2x^2-5x equation: 



x^2-5x=2x^2-5x

We move all terms to the left:

x^2-5x-(2x^2-5x)=0

We get rid of parentheses

x^2-2x^2-5x+5x=0

We add all the numbers together, and all the variables

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$

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